16t^2-160t-384=0

Solution for 16t^2-160t-384=0 equation:

16t^2-160t-384=0

a = 16; b = -160; c = -384;
Δ = b2-4ac
Δ = -1602-4·16·(-384)
Δ = 50176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50176}=224$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-224}{2*16}=\frac{-64}{32}
=-2
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+224}{2*16}=\frac{384}{32}
=12
$